ØØ Explanation :
·
Consider that a word of data is present in the
AX register and byte of data is present in the BL register, we have to divide
word in AX with the byte in BL.
·
Using DIV instruction, divide the contents of
two register. Result of division is stored in the AX register. AL contains the
quotient and AH contains the remainder.
·
Display the result using display routine.
AX = 000F H (i.e. 15)
|
08
|
) 000 F (
|
01
|
BL = 08 H
|
|
– 08
|
¯
Quotient
|
|
Remainder
|
07
|
|
ØØ Algorithm :
Step I : Initialise the data segment.
Step II : Get the first number in AX register i.e.
dividend.
Step III : Get the second number in BL i.e.
divisor.
Step IV : Divide the two numbers.
Step V : Display the result.
Step VI : Stop
ØØ Flowchart : Refer
flowchart
ØØ Program :
.model small
.data
a dw 000FH
b db 08H
.code
mov ax,
@data ; Initialize data section
mov ds,
ax
mov ax,
a ; Load number1 in ax
mov bl,
b ; Load number2 in bl
div bl ; divide numbers. Quotient in
al and Rem in ah
mov ch,
04h ; Count of digits to be
displayed
mov cl,
04h ; Count to roll by 4 bits
mov bx,
ax ; Result in reg bh
l2: rol bx,
cl ; roll bl so that msb comes
to lsb
mov dl,
bl ; load dl with data to be
displayed
and dl,
0fH ; get only lsb
cmp dl,
09 ; check if digit is 0-9 or
letter A-F
jbe l4
add dl,
07 ; if letter add 37H else only
add 30H
l4: add dl,
30H
mov ah,
02 ; Function 2 under INT 21H
(Display character)
int 21H
dec ch ; Decrement Count
jnz l2
mov ah,
4cH ; Terminate Program
int 21H
end
ØØ Result :
C:\mbs>tasm
16by8div.asm
Turbo
Assembler Version 3.0 Copyright (c) 1988, 1991 Borland
International
Assembling
file: 16by8div.asm
Error
messages: None
Warning
messages: None
Passes: 1
Remaining
memory: 438k
C:\mbs>tlink
16by8div
Turbo
Link Version 3.0 Copyright (c) 1987,
1990 Borland International
Warning: No
stack
C:\mbs>16by8div
0701