Android Secret codes



Android Secret codes
1.
Phone Information, Usage and Battery
 *#*#4636#*#*
2.
IMEI Number
 *#06#
3.
Enter Service Menu On Newer Phones
 *#0*#
4.
Detailed Camera Information
*#*#34971539#*#*
5.
Backup All Media Files


Android Secret codes
1.
Phone Information, Usage and Battery
 *#*#4636#*#*
2.
IMEI Number
 *#06#
3.
Enter Service Menu On Newer Phones
 *#0*#
4.
Detailed Camera Information
*#*#34971539#*#*
5.
Backup All Media Files

How to Convert FAT partiton to NTFS Partition without losing data




How to Convert FAT partiton to NTFS Partition without losing data
*.NTFS(NT File System) is the standard file sytem for Microsoft¡¯s Windows XP and Windows Vista operating systems.NTFS file system provides more stability, security and less fragmentation than previous FAT(File Allocation Table) file system used in operating systems like MS-DOS,Windows 98,Windows ME etc.
*.NTFS is the recommended file system for Windows XP and Windows Vista operating systems because it¡¯s is more powerful than FAT or FAT32 file systems used in former Windows OS¡¯s, and includes features required for hosting Active Directory as well as other important security features.Windows Vista needed NTFS file system in order to install and we can¡¯t install Windows Vista on a FAT partition.
*.Converting a partition from FAT or FAT32 to NTFS can be done by an inbuilt utility(convert.exe) in the Windows XP operating system.So if you want increased security and faster data encryption,go ahead and convert to NTFS.




How to Convert FAT partiton to NTFS Partition without losing data
*.NTFS(NT File System) is the standard file sytem for Microsoft¡¯s Windows XP and Windows Vista operating systems.NTFS file system provides more stability, security and less fragmentation than previous FAT(File Allocation Table) file system used in operating systems like MS-DOS,Windows 98,Windows ME etc.
*.NTFS is the recommended file system for Windows XP and Windows Vista operating systems because it¡¯s is more powerful than FAT or FAT32 file systems used in former Windows OS¡¯s, and includes features required for hosting Active Directory as well as other important security features.Windows Vista needed NTFS file system in order to install and we can¡¯t install Windows Vista on a FAT partition.
*.Converting a partition from FAT or FAT32 to NTFS can be done by an inbuilt utility(convert.exe) in the Windows XP operating system.So if you want increased security and faster data encryption,go ahead and convert to NTFS.

how to hack windows 7 admin password


Hey Guys..today,i m posting my brand new hack of admin/user paswrd in windows7. This works 1000%.Anyway i ll try 2 present it as simple as posible. Step wise instruction wid SCREENSHOT . Folo it prprly and try at ur own risk!!! : --
1. First of all, you must have a bootable Ubuntu OS CD or DVD or a USB flash drive. If you dont have it, you can download it from http://www.ubuntu.com and burn it to a CD or DVD or copy it on a USB flash drive by using UNetbootin software.This tool is available in several websites.But I have downloaded it from http://www.download.com and here is the direct download link 4 unbuntu :

Hey Guys..today,i m posting my brand new hack of admin/user paswrd in windows7. This works 1000%.Anyway i ll try 2 present it as simple as posible. Step wise instruction wid SCREENSHOT . Folo it prprly and try at ur own risk!!! : --
1. First of all, you must have a bootable Ubuntu OS CD or DVD or a USB flash drive. If you dont have it, you can download it from http://www.ubuntu.com and burn it to a CD or DVD or copy it on a USB flash drive by using UNetbootin software.This tool is available in several websites.But I have downloaded it from http://www.download.com and here is the direct download link 4 unbuntu :

Hack All nokia s60v5,Belle FP1,Belle FP2


Many User Get Certificate Error,Expired Certificate,Unable To Install Inbuilt Error Etc
So We have started to solve this problem many users r dnt how to hack ur s60v5 device..


Many User Get Certificate Error,Expired Certificate,Unable To Install Inbuilt Error Etc
So We have started to solve this problem many users r dnt how to hack ur s60v5 device..

8086 program to Multiply two 16 bit numbers




ØØ       Explanation :
·           Consider that a word of data is present in the AX register and 2nd word of data is present in the BX register.
·           We have to multiply the word in AX with the word in BX. Using MUL instruction, multiply the contents of the 2 registers.
·           The multiplication of the two 16 bit numbers may result into a 32 bit number. So result is stored in the DX and AX register.



ØØ       Explanation :
·           Consider that a word of data is present in the AX register and 2nd word of data is present in the BX register.
·           We have to multiply the word in AX with the word in BX. Using MUL instruction, multiply the contents of the 2 registers.
·           The multiplication of the two 16 bit numbers may result into a 32 bit number. So result is stored in the DX and AX register.

8086 program to Subtract two 16 bit numbers



ØØ       Explanation :
·            Consider that a word of data is present in the AX register and second word of data is present in the BX register.
·            We have to subtract the word in BX with the word AX.
·            Using subtract (SUB) instruction, subtract the contents of two registers.
·            Result will be stored in the AX register.


ØØ       Explanation :
·            Consider that a word of data is present in the AX register and second word of data is present in the BX register.
·            We have to subtract the word in BX with the word AX.
·            Using subtract (SUB) instruction, subtract the contents of two registers.
·            Result will be stored in the AX register.

8086 program to Add two 16 bit numbers



ØØ       Explanation :
·            Consider that a word of data is present in the AX register and a 2nd word of data is present in the BX register.
·            We have to add word in AX with the word in BX. Using ADD instruction, add the contents.
·            Result will be stored in the AX register. Display the result using display routine.


ØØ       Explanation :
·            Consider that a word of data is present in the AX register and a 2nd word of data is present in the BX register.
·            We have to add word in AX with the word in BX. Using ADD instruction, add the contents.
·            Result will be stored in the AX register. Display the result using display routine.

8086 program to Divide 16 bit numbers by an 8 bit numbers



ØØ       Explanation :
·            Consider that a word of data is present in the AX register and byte of data is present in the BL register, we have to divide word in AX with the byte in BL.
·            Using DIV instruction, divide the contents of two register. Result of division is stored in the AX register. AL contains the quotient and AH contains the remainder.
·            Display the result using display routine.
AX = 000F H (i.e. 15)
08
) 000 F (
01
BL = 08 H

–    08
¯ Quotient

Remainder
07

ØØ       Algorithm :
Step I       :    Initialise the data segment.
Step II     :    Get the first number in AX register i.e. dividend.
Step III   :    Get the second number in BL i.e. divisor.                                                
Step IV    :    Divide the two numbers.
Step V     :    Display the result.
Step VI    :    Stop
ØØ       Flowchart : Refer flowchart

ØØ       Program :
.model small
.data                                                                                                       
a dw 000FH
b db 08H
.code
       mov     ax, @data      ; Initialize data section
       mov     ds, ax
       mov     ax, a             ; Load number1 in ax
       mov     bl, b             ; Load number2 in bl                                                      
       div       bl                 ; divide numbers. Quotient in al and Rem in ah
       mov     ch, 04h         ; Count of digits to be displayed
       mov     cl, 04h ; Count to roll by 4 bits
       mov     bx, ax           ; Result in reg bh
l2:    rol       bx, cl            ; roll bl so that msb comes to lsb
       mov     dl, bl            ; load dl with data to be displayed
       and      dl, 0fH ; get only lsb
       cmp     dl, 09           ; check if digit is 0-9 or letter A-F
       jbe       l4
       add      dl, 07           ; if letter add 37H else only add 30H
l4:    add      dl, 30H
       mov     ah, 02           ; Function 2 under INT 21H (Display character)
       int       21H
       dec      ch                ; Decrement Count
       jnz       l2
       mov     ah, 4cH         ; Terminate Program
       int       21H
       end
ØØ       Result :
C:\mbs>tasm 16by8div.asm
Turbo Assembler  Version 3.0  Copyright (c) 1988, 1991 Borland International
Assembling file:   16by8div.asm
Error messages:    None
Warning messages:  None
Passes:            1
Remaining memory:  438k
C:\mbs>tlink 16by8div
Turbo Link  Version 3.0 Copyright (c) 1987, 1990 Borland International
Warning: No stack
C:\mbs>16by8div
0701




ØØ       Explanation :
·            Consider that a word of data is present in the AX register and byte of data is present in the BL register, we have to divide word in AX with the byte in BL.
·            Using DIV instruction, divide the contents of two register. Result of division is stored in the AX register. AL contains the quotient and AH contains the remainder.
·            Display the result using display routine.
AX = 000F H (i.e. 15)
08
) 000 F (
01
BL = 08 H

–    08
¯ Quotient

Remainder
07

ØØ       Algorithm :
Step I       :    Initialise the data segment.
Step II     :    Get the first number in AX register i.e. dividend.
Step III   :    Get the second number in BL i.e. divisor.                                                
Step IV    :    Divide the two numbers.
Step V     :    Display the result.
Step VI    :    Stop
ØØ       Flowchart : Refer flowchart

ØØ       Program :
.model small
.data                                                                                                       
a dw 000FH
b db 08H
.code
       mov     ax, @data      ; Initialize data section
       mov     ds, ax
       mov     ax, a             ; Load number1 in ax
       mov     bl, b             ; Load number2 in bl                                                      
       div       bl                 ; divide numbers. Quotient in al and Rem in ah
       mov     ch, 04h         ; Count of digits to be displayed
       mov     cl, 04h ; Count to roll by 4 bits
       mov     bx, ax           ; Result in reg bh
l2:    rol       bx, cl            ; roll bl so that msb comes to lsb
       mov     dl, bl            ; load dl with data to be displayed
       and      dl, 0fH ; get only lsb
       cmp     dl, 09           ; check if digit is 0-9 or letter A-F
       jbe       l4
       add      dl, 07           ; if letter add 37H else only add 30H
l4:    add      dl, 30H
       mov     ah, 02           ; Function 2 under INT 21H (Display character)
       int       21H
       dec      ch                ; Decrement Count
       jnz       l2
       mov     ah, 4cH         ; Terminate Program
       int       21H
       end
ØØ       Result :
C:\mbs>tasm 16by8div.asm
Turbo Assembler  Version 3.0  Copyright (c) 1988, 1991 Borland International
Assembling file:   16by8div.asm
Error messages:    None
Warning messages:  None
Passes:            1
Remaining memory:  438k
C:\mbs>tlink 16by8div
Turbo Link  Version 3.0 Copyright (c) 1987, 1990 Borland International
Warning: No stack
C:\mbs>16by8div
0701


Blogger Tips and TricksLatest Tips And TricksBlogger Tricks