8086 Program to pack the two unpacked BCD numbers
11:34
ØØ Explanation :
·
We have two digits available in the AL and BL
registers in unpacked BCD form. The digit in BL is the LSB, whereas digit in AL
is MSB. To pack the two numbers, means to combine the two numbers.
·
To make the digit in AL as MSB we rotate it 4
times to the left. i.e. if digit = 09 H, after rotating it by a 4 times it
becomes 90 H. Now add the two numbers. Result will be packed BCD. Display the
result.
eg. : AL = 09 N
BL
= 02 H
Result = 92 H
ØØ Algorithm :
Step
I : Initialize
the data memory.
Step
II : Load
the most significant BCD digit in AL.
Step
III : Load the least significant BCD digit in BL.
Step
IV : Rotate
MSB 4 times to left.
Step
V : Add
least significant BCD digit into
; rotated number.
; rotated number.
Step
VI : Display
the result.
Step
VII : Stop.
ØØ Flowchart : Refer
flowchart 5.
ØØ Program :
.model small
.data
a db 09H
b db 02H
.code
mov ax,@data ; Initialize data section
mov ds,ax
mov al,a ; Load number1 in al
mov bl,b ; Load number2 in bl
rcl al,4 ; rotate first number 4 times to
make it 90h
add al,bl ; add numbers and result in al
mov ch,02h ; Count of digits to be displayed
mov cl,04h ; Count to roll by 4 bits
mov bh,al ; Result in reg bh
l2: rol bh,cl ; roll bl so that msb comes to lsb
mov dl,bh ; load dl with data to be displayed
and dl,0fH ; get only lsb
cmp dl,09 ; check if digit is 0-9 or letter
A-F
jbe l4
add dl,07 ; if letter add 37H else only add
30H
l4: add dl,30H
mov ah,02 ; Function 2 under INT 21H (Display
character)
int 21H
dec ch ; Decrement Count
jnz l2
mov ah,4cH ; Terminate Program
int 21H
end
ØØ Result :
C:\programs>tasm packbcd.asm
Turbo Assembler Version 3.0
Copyright (c) 1988, 1991 Borland International
Assembling file: packbcd.asm
Error messages: None
Warning messages: None
Passes: 1
Remaining memory: 438k
C:\programs>tlink packbcd.obj
Turbo Link Version 3.0 Copyright (c) 1987, 1990 Borland
International
Warning: No stack
C:\programs>packbcd
92
C:\programs>
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