8086 program to Subtract two 8 bit numbers
13:07
ØØ Explanation :
·
Consider that a byte of data is present in the
AL register and second byte of data is present in the BL register.
·
We have to subtract the byte in BL from the byte
in AL. Using sub instruction subtract the contents of two registers. Result
will be stored in the AL register.
·
Display the result using display routine.
For example :
|
AL = 0A H
|
|
0A H
|
(10)10
|
|
BL = 04 H
|
–
|
04 H
|
(4)10
|
|
|
|
06H
|
|
ØØ Algorithm :
Step 1 : Initialise
the data segment.
Step 2 : Get
the first number in AL register.
Step 3 : Get
the second number in BL register.
Step 4 : Subtract
the two numbers. Corel
– 2
Step 5 : Display
the result.
Step 6 : Stop
ØØ Flowchart : Refer
flowchart 9.
ØØ Program :
.model small
.data
a db 0AH
b db 04H
.code
mov ax, @data ;
Initialize data section
mov ds, ax
mov al, a ;
Load number1 in al
mov bl, b ;
Load number2 in bl
sub al, bl ;
subtract numbers and result in al
mov ch, 02h ;
Count of digits to be displayed
mov cl, 04h ;
Count to roll by 4 bits
mov bh, al ;
Result in reg bh
l2: rol bh, cl ;
roll bl so that msb comes to lsb
mov dl, bh ;
load dl with data to be displayed
and dl, 0fH ;
get only lsb
cmp dl, 09 ;
check if digit is 0-9 or letter A-F
jbe l4
add dl, 07 ;
if letter add 37H else only add 30H
l4: add dl, 30H
mov ah, 02 ;
Function 2 under INT 21H (Display character)
int 21H
dec ch ;
Decrement Count
jnz l2
mov ah, 4cH ;
Terminate Program
int 21H
end
ØØ Result :
C:\>tasm
8bit-sub.asm
Turbo
Assembler Version 3.0 Copyright (c) 1988, 1991 Borland
International
Assembling
file: 8bit-sub.asm
Error
messages: None
Warning
messages: None
Passes: 1
Remaining
memory: 438k
C:\>tlink
8bit-sub.obj
Turbo
Link Version 3.0 Copyright (c) 1987,
1990 Borland International
Warning: No
stack
C:\>8bit-sub
06
C:\>
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